Base | Representation |
---|---|
bin | 1101000110010100111001… |
… | …1011000000000001001101 |
3 | 1212222211221220120200210211 |
4 | 3101211032123000001031 |
5 | 3341431443301404201 |
6 | 50344202200002421 |
7 | 3014351302660450 |
oct | 321451633000115 |
9 | 55884856520724 |
10 | 14402341044301 |
11 | 4652aa9062241 |
12 | 174732aa60411 |
13 | 80619a5a83b2 |
14 | 37b111505497 |
15 | 19e9880c4651 |
hex | d194e6c004d |
14402341044301 has 8 divisors (see below), whose sum is σ = 16506981142400. Its totient is φ = 12309491647728.
The previous prime is 14402341044269. The next prime is 14402341044307. The reversal of 14402341044301 is 10344014320441.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14402341044301 - 25 = 14402341044269 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14402341044307) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2947672761 + ... + 2947677646.
It is an arithmetic number, because the mean of its divisors is an integer number (2063372642800).
Almost surely, 214402341044301 is an apocalyptic number.
It is an amenable number.
14402341044301 is a deficient number, since it is larger than the sum of its proper divisors (2104640098099).
14402341044301 is an equidigital number, since it uses as much as digits as its factorization.
14402341044301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5895350763.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 14402341044301 its reverse (10344014320441), we get a palindrome (24746355364742).
The spelling of 14402341044301 in words is "fourteen trillion, four hundred two billion, three hundred forty-one million, forty-four thousand, three hundred one".
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