Base | Representation |
---|---|
bin | 1101000110010111110110… |
… | …1111111010010111010001 |
3 | 1212222221000020122122011002 |
4 | 3101211331233322113101 |
5 | 3341440110033232223 |
6 | 50344413042231345 |
7 | 3014410053651404 |
oct | 321457557722721 |
9 | 55887006578132 |
10 | 14403135055313 |
11 | 4653376282494 |
12 | 1747510955555 |
13 | 806295c422b4 |
14 | 37b188b51d3b |
15 | 19e9d2b66e28 |
hex | d197dbfa5d1 |
14403135055313 has 4 divisors (see below), whose sum is σ = 14409292875120. Its totient is φ = 14396977235508.
The previous prime is 14403135055271. The next prime is 14403135055511. The reversal of 14403135055313 is 31355053130441.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 14403135055313 - 26 = 14403135055249 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14403135355313) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3078906395 + ... + 3078911072.
It is an arithmetic number, because the mean of its divisors is an integer number (3602323218780).
Almost surely, 214403135055313 is an apocalyptic number.
It is an amenable number.
14403135055313 is a deficient number, since it is larger than the sum of its proper divisors (6157819807).
14403135055313 is an equidigital number, since it uses as much as digits as its factorization.
14403135055313 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6157819806.
The product of its (nonzero) digits is 162000, while the sum is 38.
Adding to 14403135055313 its reverse (31355053130441), we get a palindrome (45758188185754).
The spelling of 14403135055313 in words is "fourteen trillion, four hundred three billion, one hundred thirty-five million, fifty-five thousand, three hundred thirteen".
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