Base | Representation |
---|---|
bin | 1101000110011000110110… |
… | …1010110000111101101111 |
3 | 1212222221200212020000120222 |
4 | 3101212031222300331233 |
5 | 3341441131422012201 |
6 | 50344455343001555 |
7 | 3014416506105443 |
oct | 321461552607557 |
9 | 55887625200528 |
10 | 14403402141551 |
11 | 46534a3016315 |
12 | 17475862992bb |
13 | 806309387aa7 |
14 | 37b1b23d8823 |
15 | 19e9eb32391b |
hex | d198dab0f6f |
14403402141551 has 4 divisors (see below), whose sum is σ = 15250661091072. Its totient is φ = 13556143192032.
The previous prime is 14403402141497. The next prime is 14403402141577. The reversal of 14403402141551 is 15514120430441.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14403402141551 - 210 = 14403402140527 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14403402141851) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 423629474735 + ... + 423629474768.
It is an arithmetic number, because the mean of its divisors is an integer number (3812665272768).
Almost surely, 214403402141551 is an apocalyptic number.
14403402141551 is a deficient number, since it is larger than the sum of its proper divisors (847258949521).
14403402141551 is an equidigital number, since it uses as much as digits as its factorization.
14403402141551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 847258949520.
The product of its (nonzero) digits is 38400, while the sum is 35.
Adding to 14403402141551 its reverse (15514120430441), we get a palindrome (29917522571992).
The spelling of 14403402141551 in words is "fourteen trillion, four hundred three billion, four hundred two million, one hundred forty-one thousand, five hundred fifty-one".
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