144035134254031 has 4 divisors (see below), whose sum is σ = 144040413968064. Its totient is φ = 144029854540000.

The previous prime is 144035134254013. The next prime is 144035134254131. The reversal of 144035134254031 is 130452431530441.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-144035134254031 is a prime.

It is a super-2 number, since 2×144035134254031² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (144035134254131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2639816095 + ... + 2639870656.

It is an arithmetic number, because the mean of its divisors is an integer number (36010103492016).

Almost surely, 2^{144035134254031} is an apocalyptic number.

144035134254031 is a deficient number, since it is larger than the sum of its proper divisors (5279714033).

144035134254031 is an equidigital number, since it uses as much as digits as its factorization.

144035134254031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5279714032.

The product of its (nonzero) digits is 345600, while the sum is 40.

Adding to 144035134254031 its reverse (130452431530441), we get a palindrome (274487565784472).

The spelling of 144035134254031 in words is "one hundred forty-four trillion, thirty-five billion, one hundred thirty-four million, two hundred fifty-four thousand, thirty-one".