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144040103412001 = 643224012602507
BaseRepresentation
bin100000110000000011110011…
…001100101000000100100001
3200220000002200110120122121221
4200300003303030220010201
5122334423112433141001
61230203035432215041
742224361016465546
oct4060036314500441
9626002613518557
10144040103412001
1141994079292915
12141a3b2b23a481
13624ac00b28204
14277d814836bcd
15119bc310a91a1
hex8300f3328121

144040103412001 has 4 divisors (see below), whose sum is σ = 144264116015152. Its totient is φ = 143816090808852.

The previous prime is 144040103411969. The next prime is 144040103412017. The reversal of 144040103412001 is 100214301040441.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 144040103412001 - 25 = 144040103411969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (144040103412091) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 112006300611 + ... + 112006301896.

It is an arithmetic number, because the mean of its divisors is an integer number (36066029003788).

Almost surely, 2144040103412001 is an apocalyptic number.

It is an amenable number.

144040103412001 is a deficient number, since it is larger than the sum of its proper divisors (224012603151).

144040103412001 is an equidigital number, since it uses as much as digits as its factorization.

144040103412001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 224012603150.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 144040103412001 its reverse (100214301040441), we get a palindrome (244254404452442).

The spelling of 144040103412001 in words is "one hundred forty-four trillion, forty billion, one hundred three million, four hundred twelve thousand, one".

Divisors: 1 643 224012602507 144040103412001