Base | Representation |
---|---|
bin | 11010110101000101… |
… | …11110110001001011 |
3 | 1101011211201002122020 |
4 | 31122202332301023 |
5 | 213444412140243 |
6 | 10341144055523 |
7 | 1016642106156 |
oct | 153242766113 |
9 | 41154632566 |
10 | 14404021323 |
11 | 612177045a |
12 | 295ba645a3 |
13 | 148722a953 |
14 | 9a9006c9d |
15 | 59483d283 |
hex | 35a8bec4b |
14404021323 has 4 divisors (see below), whose sum is σ = 19205361768. Its totient is φ = 9602680880.
The previous prime is 14404021283. The next prime is 14404021349. The reversal of 14404021323 is 32312040441.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14404021323 - 26 = 14404021259 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14404021293 and 14404021302.
It is not an unprimeable number, because it can be changed into a prime (14404021123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2400670218 + ... + 2400670223.
It is an arithmetic number, because the mean of its divisors is an integer number (4801340442).
Almost surely, 214404021323 is an apocalyptic number.
14404021323 is a deficient number, since it is larger than the sum of its proper divisors (4801340445).
14404021323 is an equidigital number, since it uses as much as digits as its factorization.
14404021323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4801340444.
The product of its (nonzero) digits is 2304, while the sum is 24.
Adding to 14404021323 its reverse (32312040441), we get a palindrome (46716061764).
The spelling of 14404021323 in words is "fourteen billion, four hundred four million, twenty-one thousand, three hundred twenty-three".
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