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14404111314103 = 74334752263713
BaseRepresentation
bin1101000110011011011111…
…1100000010110010110111
31220000000112021122201110001
43101212313330002302313
53341444104444022403
650345053555012131
73014443210012060
oct321466774026267
956000467581401
1014404111314103
114653827360135
12174774389a047
138063c0289214
1437b23c67d567
1519ea3d708c1d
hexd19b7f02cb7

14404111314103 has 8 divisors (see below), whose sum is σ = 16499859615008. Its totient is φ = 12317867541504.

The previous prime is 14404111314083. The next prime is 14404111314121. The reversal of 14404111314103 is 30141311140441.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14404111314103 - 25 = 14404111314071 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14404111314133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2376128826 + ... + 2376134887.

It is an arithmetic number, because the mean of its divisors is an integer number (2062482451876).

Almost surely, 214404111314103 is an apocalyptic number.

14404111314103 is a deficient number, since it is larger than the sum of its proper divisors (2095748300905).

14404111314103 is an equidigital number, since it uses as much as digits as its factorization.

14404111314103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4752264153.

The product of its (nonzero) digits is 2304, while the sum is 28.

Adding to 14404111314103 its reverse (30141311140441), we get a palindrome (44545422454544).

The spelling of 14404111314103 in words is "fourteen trillion, four hundred four billion, one hundred eleven million, three hundred fourteen thousand, one hundred three".

Divisors: 1 7 433 3031 4752263713 33265845991 2057730187729 14404111314103