144110113000041 has 4 divisors (see below), whose sum is σ = 192146817333392. Its totient is φ = 96073408666692.

The previous prime is 144110113000037. The next prime is 144110113000043. The reversal of 144110113000041 is 140000311011441.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 144110113000041 - 2² = 144110113000037 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 144110112999981 and 144110113000017.

It is not an unprimeable number, because it can be changed into a prime (144110113000043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24018352166671 + ... + 24018352166676.

It is an arithmetic number, because the mean of its divisors is an integer number (48036704333348).

Almost surely, 2^{144110113000041} is an apocalyptic number.

It is an amenable number.

144110113000041 is a deficient number, since it is larger than the sum of its proper divisors (48036704333351).

144110113000041 is an equidigital number, since it uses as much as digits as its factorization.

144110113000041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 48036704333350.

The product of its (nonzero) digits is 192, while the sum is 21.

Adding to 144110113000041 its reverse (140000311011441), we get a palindrome (284110424011482).

The spelling of 144110113000041 in words is "one hundred forty-four trillion, one hundred ten billion, one hundred thirteen million, forty-one", and thus it is an aban number.