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144110113000043 is a prime number
BaseRepresentation
bin100000110001000101000000…
…000110000000101001101011
3200220020210101112222012211012
4200301011000012000221223
5122342100002412000133
61230255134424454135
742232416641250641
oct4061050006005153
9626223345865735
10144110113000043
1141a10834933593
12141b560931a34b
1362546aa24ba58
142782d76827191
15119d97c460b48
hex831140180a6b

144110113000043 has 2 divisors, whose sum is σ = 144110113000044. Its totient is φ = 144110113000042.

The previous prime is 144110113000037. The next prime is 144110113000067. The reversal of 144110113000043 is 340000311011441.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 144110113000043 - 232 = 144105818032747 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 144110112999982 and 144110113000018.

It is not a weakly prime, because it can be changed into another prime (144110113000093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72055056500021 + 72055056500022.

It is an arithmetic number, because the mean of its divisors is an integer number (72055056500022).

Almost surely, 2144110113000043 is an apocalyptic number.

144110113000043 is a deficient number, since it is larger than the sum of its proper divisors (1).

144110113000043 is an equidigital number, since it uses as much as digits as its factorization.

144110113000043 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 144110113000043 its reverse (340000311011441), we get a palindrome (484110424011484).

The spelling of 144110113000043 in words is "one hundred forty-four trillion, one hundred ten billion, one hundred thirteen million, forty-three", and thus it is an aban number.