Base | Representation |
---|---|
bin | 10100111110001001101… |
… | …001010001010001111001 |
3 | 12002202210100210222201121 |
4 | 110332021221101101321 |
5 | 142102410033411213 |
6 | 3022013134345241 |
7 | 206055244200526 |
oct | 24761151212171 |
9 | 5082710728647 |
10 | 1441123341433 |
11 | 5061a4613386 |
12 | 1b337135b221 |
13 | a5b886203b9 |
14 | 4da7207014d |
15 | 2774858d88d |
hex | 14f89a51479 |
1441123341433 has 4 divisors (see below), whose sum is σ = 1443233332368. Its totient is φ = 1439013350500.
The previous prime is 1441123341419. The next prime is 1441123341487. The reversal of 1441123341433 is 3341433211441.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1441123341433 - 213 = 1441123333241 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1441123341533) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1054994443 + ... + 1054995808.
It is an arithmetic number, because the mean of its divisors is an integer number (360808333092).
Almost surely, 21441123341433 is an apocalyptic number.
It is an amenable number.
1441123341433 is a deficient number, since it is larger than the sum of its proper divisors (2109990935).
1441123341433 is an equidigital number, since it uses as much as digits as its factorization.
1441123341433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2109990934.
The product of its digits is 41472, while the sum is 34.
Adding to 1441123341433 its reverse (3341433211441), we get a palindrome (4782556552874).
The spelling of 1441123341433 in words is "one trillion, four hundred forty-one billion, one hundred twenty-three million, three hundred forty-one thousand, four hundred thirty-three".
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