Base | Representation |
---|---|
bin | 11010110101111100… |
… | …11111110001100001 |
3 | 1101012100021120010021 |
4 | 31122332133301201 |
5 | 214003234000101 |
6 | 10342002433441 |
7 | 1020060320434 |
oct | 153276376141 |
9 | 41170246107 |
10 | 14411234401 |
11 | 6125847783 |
12 | 2962362881 |
13 | 1488884b45 |
14 | 9a9d6381b |
15 | 5952b55a1 |
hex | 35af9fc61 |
14411234401 has 4 divisors (see below), whose sum is σ = 14422161600. Its totient is φ = 14400307204.
The previous prime is 14411234363. The next prime is 14411234447. The reversal of 14411234401 is 10443211441.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10443211441 = 13 ⋅803323957.
It is a cyclic number.
It is not a de Polignac number, because 14411234401 - 213 = 14411226209 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14411234491) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5461621 + ... + 5464258.
It is an arithmetic number, because the mean of its divisors is an integer number (3605540400).
Almost surely, 214411234401 is an apocalyptic number.
It is an amenable number.
14411234401 is a deficient number, since it is larger than the sum of its proper divisors (10927199).
14411234401 is a wasteful number, since it uses less digits than its factorization.
14411234401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10927198.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 14411234401 its reverse (10443211441), we get a palindrome (24854445842).
The spelling of 14411234401 in words is "fourteen billion, four hundred eleven million, two hundred thirty-four thousand, four hundred one".
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