14412041541203 has 4 divisors (see below), whose sum is σ = 14414535411240. Its totient is φ = 14409547671168.

The previous prime is 14412041541199. The next prime is 14412041541253. The reversal of 14412041541203 is 30214514021441.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14412041541203 - 2² = 14412041541199 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14412041541203.

It is not an unprimeable number, because it can be changed into a prime (14412041541253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1246926350 + ... + 1246937907.

It is an arithmetic number, because the mean of its divisors is an integer number (3603633852810).

Almost surely, 2^{14412041541203} is an apocalyptic number.

14412041541203 is a deficient number, since it is larger than the sum of its proper divisors (2493870037).

14412041541203 is an equidigital number, since it uses as much as digits as its factorization.

14412041541203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2493870036.

The product of its (nonzero) digits is 15360, while the sum is 32.

Adding to 14412041541203 its reverse (30214514021441), we get a palindrome (44626555562644).

The spelling of 14412041541203 in words is "fourteen trillion, four hundred twelve billion, forty-one million, five hundred forty-one thousand, two hundred three".