14412051520431 has 4 divisors (see below), whose sum is σ = 19216068693912. Its totient is φ = 9608034346952.

The previous prime is 14412051520369. The next prime is 14412051520457. The reversal of 14412051520431 is 13402515021441.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14412051520431 - 2¹⁵ = 14412051487663 is a prime.

It is a super-3 number, since 3×14412051520431³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 14412051520392 and 14412051520401.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14412051520831) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2402008586736 + ... + 2402008586741.

It is an arithmetic number, because the mean of its divisors is an integer number (4804017173478).

Almost surely, 2^{14412051520431} is an apocalyptic number.

14412051520431 is a deficient number, since it is larger than the sum of its proper divisors (4804017173481).

14412051520431 is an equidigital number, since it uses as much as digits as its factorization.

14412051520431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4804017173480.

The product of its (nonzero) digits is 19200, while the sum is 33.

Adding to 14412051520431 its reverse (13402515021441), we get a palindrome (27814566541872).

The spelling of 14412051520431 in words is "fourteen trillion, four hundred twelve billion, fifty-one million, five hundred twenty thousand, four hundred thirty-one".