Base | Representation |
---|---|
bin | 1000011000111001110… |
… | …1111110011000011101 |
3 | 111210000021000001120011 |
4 | 2012032131332120131 |
5 | 4330131240040013 |
6 | 150113144323221 |
7 | 13261350001135 |
oct | 2061635763035 |
9 | 453007001504 |
10 | 144124143133 |
11 | 561393599a3 |
12 | 23b22a73511 |
13 | 1078b12b389 |
14 | 6d93259ac5 |
15 | 3b37d19c3d |
hex | 218e77e61d |
144124143133 has 4 divisors (see below), whose sum is σ = 146566925280. Its totient is φ = 141681360988.
The previous prime is 144124143127. The next prime is 144124143143. The reversal of 144124143133 is 331341421441.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 144124143133 - 25 = 144124143101 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 144124143095 and 144124143104.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (144124143103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1221390985 + ... + 1221391102.
It is an arithmetic number, because the mean of its divisors is an integer number (36641731320).
Almost surely, 2144124143133 is an apocalyptic number.
It is an amenable number.
144124143133 is a deficient number, since it is larger than the sum of its proper divisors (2442782147).
144124143133 is an equidigital number, since it uses as much as digits as its factorization.
144124143133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2442782146.
The product of its digits is 13824, while the sum is 31.
Adding to 144124143133 its reverse (331341421441), we get a palindrome (475465564574).
The spelling of 144124143133 in words is "one hundred forty-four billion, one hundred twenty-four million, one hundred forty-three thousand, one hundred thirty-three".
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