Base | Representation |
---|---|
bin | 1101000111000010110011… |
… | …1000101011100110110011 |
3 | 1220001000202200002020000010 |
4 | 3101300230320223212303 |
5 | 3342132212301122210 |
6 | 50354001020430003 |
7 | 3015265536303636 |
oct | 321605470534663 |
9 | 56030680066003 |
10 | 14414663301555 |
11 | 465825170a520 |
12 | 17497a96a8303 |
13 | 8073b243168a |
14 | 37b95dc4bc1d |
15 | 19ee59c9d920 |
hex | d1c2ce2b9b3 |
14414663301555 has 32 divisors (see below), whose sum is σ = 25586582641920. Its totient is φ = 6870471255680.
The previous prime is 14414663301547. The next prime is 14414663301587. The reversal of 14414663301555 is 55510336641441.
It is not a de Polignac number, because 14414663301555 - 23 = 14414663301547 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 740342772 + ... + 740362241.
It is an arithmetic number, because the mean of its divisors is an integer number (799580707560).
Almost surely, 214414663301555 is an apocalyptic number.
14414663301555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
14414663301555 is a deficient number, since it is larger than the sum of its proper divisors (11171919340365).
14414663301555 is a wasteful number, since it uses less digits than its factorization.
14414663301555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1480705091.
The product of its (nonzero) digits is 2592000, while the sum is 48.
Adding to 14414663301555 its reverse (55510336641441), we get a palindrome (69924999942996).
The spelling of 14414663301555 in words is "fourteen trillion, four hundred fourteen billion, six hundred sixty-three million, three hundred one thousand, five hundred fifty-five".
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