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1442013978635 = 5288402795727
BaseRepresentation
bin10100111110111110101…
…110110010000000001011
312002212002102201001021122
4110332332232302000023
5142111221034304020
63022241352025455
7206116310402456
oct24767656620013
95085072631248
101442013978635
1150661133028a
121b357b69228b
13a5c9acb9269
144db1847049d
152779b86b125
hex14fbebb200b

1442013978635 has 4 divisors (see below), whose sum is σ = 1730416774368. Its totient is φ = 1153611182904.

The previous prime is 1442013978631. The next prime is 1442013978649. The reversal of 1442013978635 is 5368793102441.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1442013978635 - 22 = 1442013978631 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1442013978631) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 144201397859 + ... + 144201397868.

It is an arithmetic number, because the mean of its divisors is an integer number (432604193592).

It is a 1-persistent number, because it is pandigital, but 2⋅1442013978635 = 2884027957270 is not.

Almost surely, 21442013978635 is an apocalyptic number.

1442013978635 is a deficient number, since it is larger than the sum of its proper divisors (288402795733).

1442013978635 is an equidigital number, since it uses as much as digits as its factorization.

1442013978635 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 288402795732.

The product of its (nonzero) digits is 4354560, while the sum is 53.

The spelling of 1442013978635 in words is "one trillion, four hundred forty-two billion, thirteen million, nine hundred seventy-eight thousand, six hundred thirty-five".

Divisors: 1 5 288402795727 1442013978635