Base | Representation |
---|---|
bin | 1101000111011110001011… |
… | …1011000000100010111111 |
3 | 1220001201201211120122212011 |
4 | 3101313202323000202333 |
5 | 3342242240124112343 |
6 | 50401214143552051 |
7 | 3015645624112216 |
oct | 321674273004277 |
9 | 56051654518764 |
10 | 14422012332223 |
11 | 4660382a86a91 |
12 | 174b0ba8bb627 |
13 | 807cb3b41532 |
14 | 37c059ca207d |
15 | 1a023a05e29d |
hex | d1de2ec08bf |
14422012332223 has 4 divisors (see below), whose sum is σ = 14424487370200. Its totient is φ = 14419537294248.
The previous prime is 14422012332193. The next prime is 14422012332229. The reversal of 14422012332223 is 32223321022441.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14422012332223 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14422012332229) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1237510248 + ... + 1237521901.
It is an arithmetic number, because the mean of its divisors is an integer number (3606121842550).
Almost surely, 214422012332223 is an apocalyptic number.
14422012332223 is a deficient number, since it is larger than the sum of its proper divisors (2475037977).
14422012332223 is an equidigital number, since it uses as much as digits as its factorization.
14422012332223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2475037976.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 14422012332223 its reverse (32223321022441), we get a palindrome (46645333354664).
The spelling of 14422012332223 in words is "fourteen trillion, four hundred twenty-two billion, twelve million, three hundred thirty-two thousand, two hundred twenty-three".
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