1442312132441 has 4 divisors (see below), whose sum is σ = 1442540244432. Its totient is φ = 1442084020452.

The previous prime is 1442312132399. The next prime is 1442312132447.

1442312132441 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1442312132441 - 2¹⁸ = 1442311870297 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1442312132398 and 1442312132407.

It is not an unprimeable number, because it can be changed into a prime (1442312132447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 114046511 + ... + 114059156.

It is an arithmetic number, because the mean of its divisors is an integer number (360635061108).

Almost surely, 2^{1442312132441} is an apocalyptic number.

It is an amenable number.

1442312132441 is a deficient number, since it is larger than the sum of its proper divisors (228111991).

1442312132441 is an equidigital number, since it uses as much as digits as its factorization.

1442312132441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 228111990.

The product of its digits is 18432, while the sum is 32.

The spelling of 1442312132441 in words is "one trillion, four hundred forty-two billion, three hundred twelve million, one hundred thirty-two thousand, four hundred forty-one".