14423122132441 has 4 divisors (see below), whose sum is σ = 15734315053584. Its totient is φ = 13111929211300.

The previous prime is 14423122132429. The next prime is 14423122132469.

14423122132441 is nontrivially palindromic in base 10.

14423122132441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14423122132441 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14423122132397 and 14423122132406.

It is not an unprimeable number, because it can be changed into a prime (14423122132841) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 655596460555 + ... + 655596460576.

It is an arithmetic number, because the mean of its divisors is an integer number (3933578763396).

Almost surely, 2^{14423122132441} is an apocalyptic number.

14423122132441 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

14423122132441 is a deficient number, since it is larger than the sum of its proper divisors (1311192921143).

14423122132441 is a wasteful number, since it uses less digits than its factorization.

14423122132441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1311192921142.

The product of its digits is 36864, while the sum is 34.

It can be divided in two parts, 1442312 and 2132441, that added together give a palindrome (3574753).

The spelling of 14423122132441 in words is "fourteen trillion, four hundred twenty-three billion, one hundred twenty-two million, one hundred thirty-two thousand, four hundred forty-one".