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144305213455 = 5132220080207
BaseRepresentation
bin1000011001100101000…
…0101101000000001111
3111210110212201101100101
42012121100231000033
54331014113312310
6150143133311531
713266006035014
oct2063120550017
9453425641311
10144305213455
1156221592797
1223b736355a7
13107b97b8490
146dad31170b
153b48b8543a
hex219942d00f

144305213455 has 8 divisors (see below), whose sum is σ = 186486737472. Its totient is φ = 106563849888.

The previous prime is 144305213441. The next prime is 144305213501. The reversal of 144305213455 is 554312503441.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 144305213455 - 221 = 144303116303 is a prime.

It is a super-2 number, since 2×1443052134552 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1110040039 + ... + 1110040168.

It is an arithmetic number, because the mean of its divisors is an integer number (23310842184).

Almost surely, 2144305213455 is an apocalyptic number.

144305213455 is a deficient number, since it is larger than the sum of its proper divisors (42181524017).

144305213455 is a wasteful number, since it uses less digits than its factorization.

144305213455 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2220080225.

The product of its (nonzero) digits is 144000, while the sum is 37.

Adding to 144305213455 its reverse (554312503441), we get a palindrome (698617716896).

The spelling of 144305213455 in words is "one hundred forty-four billion, three hundred five million, two hundred thirteen thousand, four hundred fifty-five".

Divisors: 1 5 13 65 2220080207 11100401035 28861042691 144305213455