Base | Representation |
---|---|
bin | 1101001000000000110010… |
… | …0001000101001011011010 |
3 | 1220002121201010011211001000 |
4 | 3102000030201011023122 |
5 | 3342420300312104424 |
6 | 50405351525205430 |
7 | 3016425033001503 |
oct | 322001441051332 |
9 | 56077633154030 |
10 | 14431300113114 |
11 | 4664309766265 |
12 | 1750a71260876 |
13 | 808b34101981 |
14 | 37c69b5c9baa |
15 | 1a05d06343c9 |
hex | d200c8452da |
14431300113114 has 16 divisors (see below), whose sum is σ = 32069555807040. Its totient is φ = 4810433371020.
The previous prime is 14431300113071. The next prime is 14431300113137. The reversal of 14431300113114 is 41131100313441.
14431300113114 is a `hidden beast` number, since 1 + 4 + 4 + 31 + 300 + 11 + 311 + 4 = 666.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 133623149142 + ... + 133623149249.
It is an arithmetic number, because the mean of its divisors is an integer number (2004347237940).
Almost surely, 214431300113114 is an apocalyptic number.
14431300113114 is an abundant number, since it is smaller than the sum of its proper divisors (17638255693926).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14431300113114 is a wasteful number, since it uses less digits than its factorization.
14431300113114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 267246298402 (or 267246298396 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 27.
Adding to 14431300113114 its reverse (41131100313441), we get a palindrome (55562400426555).
The spelling of 14431300113114 in words is "fourteen trillion, four hundred thirty-one billion, three hundred million, one hundred thirteen thousand, one hundred fourteen".
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