Base | Representation |
---|---|
bin | 1000011001100111000… |
… | …0000100000000000001 |
3 | 111210111110012000222012 |
4 | 2012121300010000001 |
5 | 4331023214342423 |
6 | 150144025422305 |
7 | 13266135643652 |
oct | 2063160040001 |
9 | 453443160865 |
10 | 144313434113 |
11 | 56226198022 |
12 | 23b7633a995 |
13 | 107bb406184 |
14 | 6db0451529 |
15 | 3b4975b078 |
hex | 2199c04001 |
144313434113 has 4 divisors (see below), whose sum is σ = 144321152448. Its totient is φ = 144305715780.
The previous prime is 144313434103. The next prime is 144313434191. The reversal of 144313434113 is 311434313441.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 144313434113 - 220 = 144312385537 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 144313434113.
It is not an unprimeable number, because it can be changed into a prime (144313434103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3831053 + ... + 3868538.
It is an arithmetic number, because the mean of its divisors is an integer number (36080288112).
Almost surely, 2144313434113 is an apocalyptic number.
It is an amenable number.
144313434113 is a deficient number, since it is larger than the sum of its proper divisors (7718335).
144313434113 is an equidigital number, since it uses as much as digits as its factorization.
144313434113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7718334.
The product of its digits is 20736, while the sum is 32.
Adding to 144313434113 its reverse (311434313441), we get a palindrome (455747747554).
The spelling of 144313434113 in words is "one hundred forty-four billion, three hundred thirteen million, four hundred thirty-four thousand, one hundred thirteen".
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