144331053001 has 4 divisors (see below), whose sum is σ = 144521715652. Its totient is φ = 144140390352.

The previous prime is 144331052993. The next prime is 144331053017. The reversal of 144331053001 is 100350133441.

144331053001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 100350133441 = 29 ⋅3460349429.

It can be written as a sum of positive squares in 2 ways, for example, as 76040820025 + 68290232976 = 275755^2 + 261324^2 .

It is a cyclic number.

It is not a de Polignac number, because 144331053001 - 2³ = 144331052993 is a prime.

It is a super-2 number, since 2×144331053001² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (144331053091) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95330190 + ... + 95331703.

It is an arithmetic number, because the mean of its divisors is an integer number (36130428913).

Almost surely, 2^144331053001 is an apocalyptic number.

It is an amenable number.

144331053001 is a deficient number, since it is larger than the sum of its proper divisors (190662651).

144331053001 is an equidigital number, since it uses as much as digits as its factorization.

144331053001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 190662650.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 144331053001 its reverse (100350133441), we get a palindrome (244681186442).

The spelling of 144331053001 in words is "one hundred forty-four billion, three hundred thirty-one million, fifty-three thousand, one".