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14433143443322 = 27216571721661
BaseRepresentation
bin1101001000000111101001…
…1000110100111101111010
31220002210110120201200201012
43102001322120310331322
53342433034210141242
650410254454153522
73016521515024162
oct322017230647572
956083416650635
1014433143443322
11466507522555a
1217512a66528a2
13809068c832c6
1437c7d43415a2
151a068c39b282
hexd207a634f7a

14433143443322 has 4 divisors (see below), whose sum is σ = 21649715164986. Its totient is φ = 7216571721660.

The previous prime is 14433143443319. The next prime is 14433143443339. The reversal of 14433143443322 is 22334434133441.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 13599064911481 + 834078531841 = 3687691^2 + 913279^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 14433143443322.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3608285860829 + ... + 3608285860832.

Almost surely, 214433143443322 is an apocalyptic number.

14433143443322 is a deficient number, since it is larger than the sum of its proper divisors (7216571721664).

14433143443322 is an equidigital number, since it uses as much as digits as its factorization.

14433143443322 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7216571721663.

The product of its digits is 995328, while the sum is 41.

Adding to 14433143443322 its reverse (22334434133441), we get a palindrome (36767577576763).

The spelling of 14433143443322 in words is "fourteen trillion, four hundred thirty-three billion, one hundred forty-three million, four hundred forty-three thousand, three hundred twenty-two".

Divisors: 1 2 7216571721661 14433143443322