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144332024011 = 720618860573
BaseRepresentation
bin1000011001101011011…
…0111110100011001011
3111210112202011111111221
42012122312332203023
54331042444232021
6150145532102511
713266452650630
oct2063266764313
9453482144457
10144332024011
115623573497a
1223b80604a37
13107c2214806
146db2ad0187
153b4b1ce241
hex219adbe8cb

144332024011 has 4 divisors (see below), whose sum is σ = 164950884592. Its totient is φ = 123713163432.

The previous prime is 144332023999. The next prime is 144332024159. The reversal of 144332024011 is 110420233441.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 144332024011 - 231 = 142184540363 is a prime.

It is a super-2 number, since 2×1443320240112 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (144332024611) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10309430280 + ... + 10309430293.

It is an arithmetic number, because the mean of its divisors is an integer number (41237721148).

Almost surely, 2144332024011 is an apocalyptic number.

144332024011 is a deficient number, since it is larger than the sum of its proper divisors (20618860581).

144332024011 is an equidigital number, since it uses as much as digits as its factorization.

144332024011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20618860580.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 144332024011 its reverse (110420233441), we get a palindrome (254752257452).

The spelling of 144332024011 in words is "one hundred forty-four billion, three hundred thirty-two million, twenty-four thousand, eleven".

Divisors: 1 7 20618860573 144332024011