14433401401 has 4 divisors (see below), whose sum is σ = 14525334052. Its totient is φ = 14341468752.

The previous prime is 14433401377. The next prime is 14433401473. The reversal of 14433401401 is 10410433441.

14433401401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 10410433441 = 593 ⋅17555537.

It can be written as a sum of positive squares in 2 ways, for example, as 8817397801 + 5616003600 = 93901^2 + 74940^2 .

It is a cyclic number.

It is not a de Polignac number, because 14433401401 - 2¹¹ = 14433399353 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14433401201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45966090 + ... + 45966403.

It is an arithmetic number, because the mean of its divisors is an integer number (3631333513).

Almost surely, 2^14433401401 is an apocalyptic number.

It is an amenable number.

14433401401 is a deficient number, since it is larger than the sum of its proper divisors (91932651).

14433401401 is an equidigital number, since it uses as much as digits as its factorization.

14433401401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 91932650.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 14433401401 its reverse (10410433441), we get a palindrome (24843834842).

The spelling of 14433401401 in words is "fourteen billion, four hundred thirty-three million, four hundred one thousand, four hundred one".