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14434012433 = 58786328493
BaseRepresentation
bin11010111000101010…
…11000110100010001
31101020221010210201002
431130111120310101
5214030101344213
610344134551345
71020455036621
oct153425306421
941227123632
1014434012433
1161376951a5
122969b08555
1314904cb879
149acdb2881
155972b4658
hex35c558d11

14434012433 has 8 divisors (see below), whose sum is σ = 14475863808. Its totient is φ = 14392220944.

The previous prime is 14434012361. The next prime is 14434012459. The reversal of 14434012433 is 33421043441.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14434012433 - 226 = 14366903569 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14434012396 and 14434012405.

It is not an unprimeable number, because it can be changed into a prime (14434012493) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 492335 + ... + 520827.

It is an arithmetic number, because the mean of its divisors is an integer number (1809482976).

Almost surely, 214434012433 is an apocalyptic number.

It is an amenable number.

14434012433 is a deficient number, since it is larger than the sum of its proper divisors (41851375).

14434012433 is an equidigital number, since it uses as much as digits as its factorization.

14434012433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29943.

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 14434012433 its reverse (33421043441), we get a palindrome (47855055874).

The spelling of 14434012433 in words is "fourteen billion, four hundred thirty-four million, twelve thousand, four hundred thirty-three".

Divisors: 1 587 863 28493 506581 16725391 24589459 14434012433