Base | Representation |
---|---|
bin | 10101000000010010000… |
… | …011110110110101111011 |
3 | 12002222200212100112002101 |
4 | 111000102003312311323 |
5 | 142122101433344121 |
6 | 3023032212444231 |
7 | 206166044445625 |
oct | 25002203666573 |
9 | 5088625315071 |
10 | 1443412012411 |
11 | 5071694a67a6 |
12 | 1b38ab919677 |
13 | a6161829a95 |
14 | 4dc0bdcdc15 |
15 | 2782e473491 |
hex | 150120f6d7b |
1443412012411 has 4 divisors (see below), whose sum is σ = 1459630125000. Its totient is φ = 1427193899824.
The previous prime is 1443412012397. The next prime is 1443412012421. The reversal of 1443412012411 is 1142102143441.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1443412012411 - 25 = 1443412012379 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1443412012411.
It is not an unprimeable number, because it can be changed into a prime (1443412012421) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8109056161 + ... + 8109056338.
It is an arithmetic number, because the mean of its divisors is an integer number (364907531250).
Almost surely, 21443412012411 is an apocalyptic number.
1443412012411 is a deficient number, since it is larger than the sum of its proper divisors (16218112589).
1443412012411 is an equidigital number, since it uses as much as digits as its factorization.
1443412012411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16218112588.
The product of its (nonzero) digits is 3072, while the sum is 28.
Adding to 1443412012411 its reverse (1142102143441), we get a palindrome (2585514155852).
The spelling of 1443412012411 in words is "one trillion, four hundred forty-three billion, four hundred twelve million, twelve thousand, four hundred eleven".
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