Search a number
-
+
144352020253 = 731724755963
BaseRepresentation
bin1000011001110000001…
…1010000011100011101
3111210121010210102012111
42012130003100130131
54331113104122003
6150151524434021
713300114633000
oct2063403203435
9453533712174
10144352020253
1156245a523a1
1223b87248911
13107c63c62cc
146db5617537
153b4cd2de6d
hex219c0d071d

144352020253 has 16 divisors (see below), whose sum is σ = 178242940800. Its totient is φ = 116452045248.

The previous prime is 144352020251. The next prime is 144352020299. The reversal of 144352020253 is 352020253441.

It is not a de Polignac number, because 144352020253 - 21 = 144352020251 is a prime.

It is a super-2 number, since 2×1443520202532 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (144352020251) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12372151 + ... + 12383812.

It is an arithmetic number, because the mean of its divisors is an integer number (11140183800).

Almost surely, 2144352020253 is an apocalyptic number.

It is an amenable number.

144352020253 is a deficient number, since it is larger than the sum of its proper divisors (33890920547).

144352020253 is an equidigital number, since it uses as much as digits as its factorization.

144352020253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24756001 (or 24755987 counting only the distinct ones).

The product of its (nonzero) digits is 28800, while the sum is 31.

Adding to 144352020253 its reverse (352020253441), we get a palindrome (496372273694).

The spelling of 144352020253 in words is "one hundred forty-four billion, three hundred fifty-two million, twenty thousand, two hundred fifty-three".

Divisors: 1 7 17 49 119 343 833 5831 24755963 173291741 420851371 1213042187 2945959597 8491295309 20621717179 144352020253