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144353004421 = 567832542187
BaseRepresentation
bin1000011001110000011…
…1000000101110000101
3111210121012122102020011
42012130013000232011
54331113332120141
6150152001510221
713300126202203
oct2063407005605
9453535572204
10144353004421
115624656485a
1223b87642371
13107c667c262
146db57d2073
153b4ce75881
hex219c1c0b85

144353004421 has 4 divisors (see below), whose sum is σ = 144355603392. Its totient is φ = 144350405452.

The previous prime is 144353004377. The next prime is 144353004427. The reversal of 144353004421 is 124400353441.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-144353004421 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (144353004427) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1214311 + ... + 1327876.

It is an arithmetic number, because the mean of its divisors is an integer number (36088900848).

Almost surely, 2144353004421 is an apocalyptic number.

It is an amenable number.

144353004421 is a deficient number, since it is larger than the sum of its proper divisors (2598971).

144353004421 is an equidigital number, since it uses as much as digits as its factorization.

144353004421 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2598970.

The product of its (nonzero) digits is 23040, while the sum is 31.

Adding to 144353004421 its reverse (124400353441), we get a palindrome (268753357862).

The spelling of 144353004421 in words is "one hundred forty-four billion, three hundred fifty-three million, four thousand, four hundred twenty-one".

Divisors: 1 56783 2542187 144353004421