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144410123131 = 819117630341
BaseRepresentation
bin1000011001111110000…
…0111001101101111011
3111210202012010100100221
42012133200321231323
54331222442420011
6150201402040511
713301421536101
oct2063740715573
9453665110327
10144410123131
11562758279aa
1223ba27a9137
131080545a901
146dbd21dc71
153b52ea9971
hex219f839b7b

144410123131 has 4 divisors (see below), whose sum is σ = 144427761664. Its totient is φ = 144392484600.

The previous prime is 144410123119. The next prime is 144410123147. The reversal of 144410123131 is 131321014441.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 144410123131 - 27 = 144410123003 is a prime.

It is a super-2 number, since 2×1444101231312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 144410123096 and 144410123105.

It is not an unprimeable number, because it can be changed into a prime (144410123171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8806980 + ... + 8823361.

It is an arithmetic number, because the mean of its divisors is an integer number (36106940416).

Almost surely, 2144410123131 is an apocalyptic number.

144410123131 is a deficient number, since it is larger than the sum of its proper divisors (17638533).

144410123131 is an equidigital number, since it uses as much as digits as its factorization.

144410123131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17638532.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 144410123131 its reverse (131321014441), we get a palindrome (275731137572).

The spelling of 144410123131 in words is "one hundred forty-four billion, four hundred ten million, one hundred twenty-three thousand, one hundred thirty-one".

Divisors: 1 8191 17630341 144410123131