Base | Representation |
---|---|
bin | 10101000000111100010… |
… | …100100011100100110011 |
3 | 12010001112021111111111121 |
4 | 111000330110203210303 |
5 | 142130024441024021 |
6 | 3023230421323111 |
7 | 206222444150236 |
oct | 25007424434463 |
9 | 5101467444447 |
10 | 1444121033011 |
11 | 5074a2747438 |
12 | 1b3a69266497 |
13 | a62456a6cb7 |
14 | 4dc7823541d |
15 | 27871828741 |
hex | 1503c523933 |
1444121033011 has 4 divisors (see below), whose sum is σ = 1449049774032. Its totient is φ = 1439192291992.
The previous prime is 1444121032999. The next prime is 1444121033039. The reversal of 1444121033011 is 1103301214441.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1444121033011 - 215 = 1444121000243 is a prime.
It is a super-2 number, since 2×14441210330112 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1444121033051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2464370071 + ... + 2464370656.
It is an arithmetic number, because the mean of its divisors is an integer number (362262443508).
Almost surely, 21444121033011 is an apocalyptic number.
1444121033011 is a deficient number, since it is larger than the sum of its proper divisors (4928741021).
1444121033011 is an equidigital number, since it uses as much as digits as its factorization.
1444121033011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4928741020.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1444121033011 its reverse (1103301214441), we get a palindrome (2547422247452).
The spelling of 1444121033011 in words is "one trillion, four hundred forty-four billion, one hundred twenty-one million, thirty-three thousand, eleven".
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