Base | Representation |
---|---|
bin | 1101001000100101110010… |
… | …0001110101000101100111 |
3 | 1220010120100022120100100022 |
4 | 3102021130201311011213 |
5 | 3343101120444434343 |
6 | 50414113253105355 |
7 | 3020226126142136 |
oct | 322113441650547 |
9 | 56116308510308 |
10 | 14441232421223 |
11 | 4668546246363 |
12 | 175298362825b |
13 | 809a57a7b06a |
14 | 37cd6076b91d |
15 | 1a09b25c0568 |
hex | d225c875167 |
14441232421223 has 4 divisors (see below), whose sum is σ = 14441403304848. Its totient is φ = 14441061537600.
The previous prime is 14441232421193. The next prime is 14441232421267. The reversal of 14441232421223 is 32212423214441.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14441232421223 - 26 = 14441232421159 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14441232426223) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85314986 + ... + 85484087.
It is an arithmetic number, because the mean of its divisors is an integer number (3610350826212).
Almost surely, 214441232421223 is an apocalyptic number.
14441232421223 is a deficient number, since it is larger than the sum of its proper divisors (170883625).
14441232421223 is an equidigital number, since it uses as much as digits as its factorization.
14441232421223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 170883624.
The product of its digits is 73728, while the sum is 35.
Adding to 14441232421223 its reverse (32212423214441), we get a palindrome (46653655635664).
The spelling of 14441232421223 in words is "fourteen trillion, four hundred forty-one billion, two hundred thirty-two million, four hundred twenty-one thousand, two hundred twenty-three".
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