144415130311 has 4 divisors (see below), whose sum is σ = 144465680992. Its totient is φ = 144364579632.

The previous prime is 144415130303. The next prime is 144415130323. The reversal of 144415130311 is 113031514441.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 113031514441 = 29 ⋅3897638429.

It is a cyclic number.

It is not a de Polignac number, because 144415130311 - 2³ = 144415130303 is a prime.

It is a super-2 number, since 2×144415130311² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 144415130311.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (144415130371) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25271055 + ... + 25276768.

It is an arithmetic number, because the mean of its divisors is an integer number (36116420248).

Almost surely, 2^144415130311 is an apocalyptic number.

144415130311 is a deficient number, since it is larger than the sum of its proper divisors (50550681).

144415130311 is an equidigital number, since it uses as much as digits as its factorization.

144415130311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 50550680.

The product of its (nonzero) digits is 2880, while the sum is 28.

Adding to 144415130311 its reverse (113031514441), we get a palindrome (257446644752).

The spelling of 144415130311 in words is "one hundred forty-four billion, four hundred fifteen million, one hundred thirty thousand, three hundred eleven".