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144423111453 = 348141037151
BaseRepresentation
bin1000011010000001001…
…0011100101100011101
3111210210002120012222220
42012200102130230131
54331234304031303
6150202544255553
713301640122655
oct2064022345435
9453702505886
10144423111453
1156282099255
1223ba70115b9
13108080576ca
146dc0c41365
153b541c3053
hex21a049cb1d

144423111453 has 4 divisors (see below), whose sum is σ = 192564148608. Its totient is φ = 96282074300.

The previous prime is 144423111449. The next prime is 144423111479. The reversal of 144423111453 is 354111324441.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 144423111453 - 22 = 144423111449 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (144423111253) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24070518573 + ... + 24070518578.

It is an arithmetic number, because the mean of its divisors is an integer number (48141037152).

Almost surely, 2144423111453 is an apocalyptic number.

It is an amenable number.

144423111453 is a deficient number, since it is larger than the sum of its proper divisors (48141037155).

144423111453 is an equidigital number, since it uses as much as digits as its factorization.

144423111453 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 48141037154.

The product of its digits is 23040, while the sum is 33.

Adding to 144423111453 its reverse (354111324441), we get a palindrome (498534435894).

The spelling of 144423111453 in words is "one hundred forty-four billion, four hundred twenty-three million, one hundred eleven thousand, four hundred fifty-three".

Divisors: 1 3 48141037151 144423111453