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14443012113 = 37365949827
BaseRepresentation
bin11010111001101111…
…01110000000010001
31101021120002000221120
431130313232000101
5214034402341423
610345055512453
71020624402015
oct153467560021
941246060846
1014443012113
116141781852
122970b28729
13149233001a
149b0276545
15597e90ee3
hex35cdee011

14443012113 has 8 divisors (see below), whose sum is σ = 19521149088. Its totient is φ = 9496774944.

The previous prime is 14443012097. The next prime is 14443012117. The reversal of 14443012113 is 31121034441.

14443012113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14443012113 - 24 = 14443012097 is a prime.

It is not an unprimeable number, because it can be changed into a prime (14443012117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 32974695 + ... + 32975132.

It is an arithmetic number, because the mean of its divisors is an integer number (2440143636).

Almost surely, 214443012113 is an apocalyptic number.

It is an amenable number.

14443012113 is a deficient number, since it is larger than the sum of its proper divisors (5078136975).

14443012113 is an equidigital number, since it uses as much as digits as its factorization.

14443012113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65949903.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 14443012113 its reverse (31121034441), we get a palindrome (45564046554).

The spelling of 14443012113 in words is "fourteen billion, four hundred forty-three million, twelve thousand, one hundred thirteen".

Divisors: 1 3 73 219 65949827 197849481 4814337371 14443012113