Base | Representation |
---|---|
bin | 11010111001110000… |
… | …01110000101010111 |
3 | 1101021120022201012011 |
4 | 31130320032011113 |
5 | 214034421043021 |
6 | 10345102405051 |
7 | 1020625460056 |
oct | 153470160527 |
9 | 41246281164 |
10 | 14443143511 |
11 | 6141861545 |
12 | 2970b90787 |
13 | 1492377a84 |
14 | 9b02ac39d |
15 | 597eb9de1 |
hex | 35ce0e157 |
14443143511 has 4 divisors (see below), whose sum is σ = 14443399224. Its totient is φ = 14442887800.
The previous prime is 14443143497. The next prime is 14443143529. The reversal of 14443143511 is 11534134441.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11534134441 = 11437 ⋅1008493.
It is a cyclic number.
It is not a de Polignac number, because 14443143511 - 213 = 14443135319 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14443143581) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1525 + ... + 169966.
It is an arithmetic number, because the mean of its divisors is an integer number (3610849806).
Almost surely, 214443143511 is an apocalyptic number.
14443143511 is a deficient number, since it is larger than the sum of its proper divisors (255713).
14443143511 is an equidigital number, since it uses as much as digits as its factorization.
14443143511 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 255712.
The product of its digits is 11520, while the sum is 31.
Adding to 14443143511 its reverse (11534134441), we get a palindrome (25977277952).
The spelling of 14443143511 in words is "fourteen billion, four hundred forty-three million, one hundred forty-three thousand, five hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •