Base | Representation |
---|---|
bin | 1101001000101101001100… |
… | …0100100100100100110011 |
3 | 1220010202110220212210222021 |
4 | 3102023103010210210303 |
5 | 3343114204114140430 |
6 | 50415042500252311 |
7 | 3020326325625013 |
oct | 322132304444463 |
9 | 56122426783867 |
10 | 14443221240115 |
11 | 4669376946438 |
12 | 17532396a1097 |
13 | 809cb3b0c085 |
14 | 37d0ac955c43 |
15 | 1a0a7bec507a |
hex | d22d3124933 |
14443221240115 has 16 divisors (see below), whose sum is σ = 17578649439648. Its totient is φ = 11390223027456.
The previous prime is 14443221240067. The next prime is 14443221240137. The reversal of 14443221240115 is 51104212234441.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14443221240115 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9855777 + ... + 11225986.
It is an arithmetic number, because the mean of its divisors is an integer number (1098665589978).
Almost surely, 214443221240115 is an apocalyptic number.
14443221240115 is a deficient number, since it is larger than the sum of its proper divisors (3135428199533).
14443221240115 is a wasteful number, since it uses less digits than its factorization.
14443221240115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21083718.
The product of its (nonzero) digits is 30720, while the sum is 34.
Adding to 14443221240115 its reverse (51104212234441), we get a palindrome (65547433474556).
The spelling of 14443221240115 in words is "fourteen trillion, four hundred forty-three billion, two hundred twenty-one million, two hundred forty thousand, one hundred fifteen".
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