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14443221240115 = 573187721081763
BaseRepresentation
bin1101001000101101001100…
…0100100100100100110011
31220010202110220212210222021
43102023103010210210303
53343114204114140430
650415042500252311
73020326325625013
oct322132304444463
956122426783867
1014443221240115
114669376946438
1217532396a1097
13809cb3b0c085
1437d0ac955c43
151a0a7bec507a
hexd22d3124933

14443221240115 has 16 divisors (see below), whose sum is σ = 17578649439648. Its totient is φ = 11390223027456.

The previous prime is 14443221240067. The next prime is 14443221240137. The reversal of 14443221240115 is 51104212234441.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14443221240115 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9855777 + ... + 11225986.

It is an arithmetic number, because the mean of its divisors is an integer number (1098665589978).

Almost surely, 214443221240115 is an apocalyptic number.

14443221240115 is a deficient number, since it is larger than the sum of its proper divisors (3135428199533).

14443221240115 is a wasteful number, since it uses less digits than its factorization.

14443221240115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21083718.

The product of its (nonzero) digits is 30720, while the sum is 34.

Adding to 14443221240115 its reverse (51104212234441), we get a palindrome (65547433474556).

The spelling of 14443221240115 in words is "fourteen trillion, four hundred forty-three billion, two hundred twenty-one million, two hundred forty thousand, one hundred fifteen".

Divisors: 1 5 73 365 1877 9385 137021 685105 21081763 105408815 1538968699 7694843495 39570469151 197852345755 2888644248023 14443221240115