Base | Representation |
---|---|
bin | 100000110101111000101001… |
… | …111100111101110110001111 |
3 | 200221102101001120212100211010 |
4 | 200311320221330331312033 |
5 | 122413003022211343203 |
6 | 1231111010055100303 |
7 | 42265323046444101 |
oct | 4065705174756617 |
9 | 627371046770733 |
10 | 144440454012303 |
11 | 4202894180a429 |
12 | 1424963b971693 |
13 | 62798a3c9ca47 |
14 | 2794d533c1571 |
15 | 11a7363659303 |
hex | 835e29f3dd8f |
144440454012303 has 4 divisors (see below), whose sum is σ = 192587272016408. Its totient is φ = 96293636008200.
The previous prime is 144440454012223. The next prime is 144440454012329. The reversal of 144440454012303 is 303210454044441.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 144440454012303 - 217 = 144440453881231 is a prime.
It is a super-2 number, since 2×1444404540123032 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (144440454012383) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24073409002048 + ... + 24073409002053.
It is an arithmetic number, because the mean of its divisors is an integer number (48146818004102).
Almost surely, 2144440454012303 is an apocalyptic number.
144440454012303 is a deficient number, since it is larger than the sum of its proper divisors (48146818004105).
144440454012303 is an equidigital number, since it uses as much as digits as its factorization.
144440454012303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 48146818004104.
The product of its (nonzero) digits is 368640, while the sum is 39.
The spelling of 144440454012303 in words is "one hundred forty-four trillion, four hundred forty billion, four hundred fifty-four million, twelve thousand, three hundred three".
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