Base | Representation |
---|---|
bin | 10101000001001110001… |
… | …110000101000011111111 |
3 | 12010002022012112220202011 |
4 | 111001032032011003333 |
5 | 142131133324400210 |
6 | 3023320305512051 |
7 | 206233051454242 |
oct | 25011616050377 |
9 | 5102265486664 |
10 | 1444421325055 |
11 | 507637200285 |
12 | 1b3b31942627 |
13 | a62929779b7 |
14 | 4dca6083259 |
15 | 2788cd93d8a |
hex | 1504e3850ff |
1444421325055 has 4 divisors (see below), whose sum is σ = 1733305590072. Its totient is φ = 1155537060040.
The previous prime is 1444421325043. The next prime is 1444421325089. The reversal of 1444421325055 is 5505231244441.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1444421325055 - 25 = 1444421325023 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1444421324999 and 1444421325017.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 144442132501 + ... + 144442132510.
It is an arithmetic number, because the mean of its divisors is an integer number (433326397518).
Almost surely, 21444421325055 is an apocalyptic number.
1444421325055 is a deficient number, since it is larger than the sum of its proper divisors (288884265017).
1444421325055 is an equidigital number, since it uses as much as digits as its factorization.
1444421325055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 288884265016.
The product of its (nonzero) digits is 384000, while the sum is 40.
Adding to 1444421325055 its reverse (5505231244441), we get a palindrome (6949652569496).
The spelling of 1444421325055 in words is "one trillion, four hundred forty-four billion, four hundred twenty-one million, three hundred twenty-five thousand, fifty-five".
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