144443000113 has 4 divisors (see below), whose sum is σ = 145363019380. Its totient is φ = 143522980848.

The previous prime is 144443000083. The next prime is 144443000131. The reversal of 144443000113 is 311000344441.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 41457846544 + 102985153569 = 203612^2 + 320913^2 .

It is a cyclic number.

It is not a de Polignac number, because 144443000113 - 2⁹ = 144442999601 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (144443004113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 460009398 + ... + 460009711.

It is an arithmetic number, because the mean of its divisors is an integer number (36340754845).

Almost surely, 2^144443000113 is an apocalyptic number.

It is an amenable number.

144443000113 is a deficient number, since it is larger than the sum of its proper divisors (920019267).

144443000113 is an equidigital number, since it uses as much as digits as its factorization.

144443000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 920019266.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 144443000113 its reverse (311000344441), we get a palindrome (455443344554).

The spelling of 144443000113 in words is "one hundred forty-four billion, four hundred forty-three million, one hundred thirteen", and thus it is an aban number.