Search a number
-
+
14445113055 = 35963007537
BaseRepresentation
bin11010111001111111…
…01110111011011111
31101021201000202220020
431130333232323133
5214040422104210
610345212523223
71020651302142
oct153477567337
941251022806
1014445113055
11614298726a
122971780513
1314928b7399
149b0662059
15598258770
hex35cfeeedf

14445113055 has 8 divisors (see below), whose sum is σ = 23112180912. Its totient is φ = 7704060288.

The previous prime is 14445113051. The next prime is 14445113077. The reversal of 14445113055 is 55031154441.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14445113055 - 22 = 14445113051 is a prime.

It is a super-2 number, since 2×144451130552 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14445113051) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 481503754 + ... + 481503783.

It is an arithmetic number, because the mean of its divisors is an integer number (2889022614).

Almost surely, 214445113055 is an apocalyptic number.

14445113055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

14445113055 is a deficient number, since it is larger than the sum of its proper divisors (8667067857).

14445113055 is an equidigital number, since it uses as much as digits as its factorization.

14445113055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 963007545.

The product of its (nonzero) digits is 24000, while the sum is 33.

Adding to 14445113055 its reverse (55031154441), we get a palindrome (69476267496).

The spelling of 14445113055 in words is "fourteen billion, four hundred forty-five million, one hundred thirteen thousand, fifty-five".

Divisors: 1 3 5 15 963007537 2889022611 4815037685 14445113055