14445531525001 has 4 divisors (see below), whose sum is σ = 14478139948752. Its totient is φ = 14412923101252.

The previous prime is 14445531524969. The next prime is 14445531525011. The reversal of 14445531525001 is 10052513554441.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14445531525001 - 2⁵ = 14445531524969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14445531525011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16304211211 + ... + 16304212096.

It is an arithmetic number, because the mean of its divisors is an integer number (3619534987188).

Almost surely, 2^{14445531525001} is an apocalyptic number.

It is an amenable number.

14445531525001 is a deficient number, since it is larger than the sum of its proper divisors (32608423751).

14445531525001 is an equidigital number, since it uses as much as digits as its factorization.

14445531525001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32608423750.

The product of its (nonzero) digits is 240000, while the sum is 40.

The spelling of 14445531525001 in words is "fourteen trillion, four hundred forty-five billion, five hundred thirty-one million, five hundred twenty-five thousand, one".