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14445531524969 is a prime number
BaseRepresentation
bin1101001000110101110011…
…0001100110111101101001
31220010222102221002102222222
43102031130301212331221
53343133422032244334
650420104025523425
73020440511003246
oct322153461467551
956128387072888
1014445531524969
11466a351a51666
121753783343575
1380a29164562c
1437d24b7005cd
151a0b64c28d2e
hexd235cc66f69

14445531524969 has 2 divisors, whose sum is σ = 14445531524970. Its totient is φ = 14445531524968.

The previous prime is 14445531524951. The next prime is 14445531525011. The reversal of 14445531524969 is 96942513554441.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12243616831744 + 2201914693225 = 3499088^2 + 1483885^2 .

It is an emirp because it is prime and its reverse (96942513554441) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14445531524969 - 232 = 14441236557673 is a prime.

It is a super-2 number, since 2×144455315249692 (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (14445531524569) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7222765762484 + 7222765762485.

It is an arithmetic number, because the mean of its divisors is an integer number (7222765762485).

Almost surely, 214445531524969 is an apocalyptic number.

It is an amenable number.

14445531524969 is a deficient number, since it is larger than the sum of its proper divisors (1).

14445531524969 is an equidigital number, since it uses as much as digits as its factorization.

14445531524969 is an evil number, because the sum of its binary digits is even.

The product of its digits is 93312000, while the sum is 62.

The spelling of 14445531524969 in words is "fourteen trillion, four hundred forty-five billion, five hundred thirty-one million, five hundred twenty-four thousand, nine hundred sixty-nine".