Base | Representation |
---|---|
bin | 1101001010000010001001… |
… | …0110010000100101000011 |
3 | 1220012221100020021101221210 |
4 | 3102200202112100211003 |
5 | 3344002410141111342 |
6 | 50433333424021203 |
7 | 3022064420064624 |
oct | 322404226204503 |
9 | 56187306241853 |
10 | 14466026113347 |
11 | 4678009681206 |
12 | 1757742a61803 |
13 | 80c1a962c0c3 |
14 | 38023356da4b |
15 | 1a14640de79c |
hex | d2822590943 |
14466026113347 has 4 divisors (see below), whose sum is σ = 19288034817800. Its totient is φ = 9644017408896.
The previous prime is 14466026113327. The next prime is 14466026113351. The reversal of 14466026113347 is 74331162066441.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 14466026113347 - 212 = 14466026109251 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14466026113296 and 14466026113305.
It is not an unprimeable number, because it can be changed into a prime (14466026113327) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2411004352222 + ... + 2411004352227.
It is an arithmetic number, because the mean of its divisors is an integer number (4822008704450).
Almost surely, 214466026113347 is an apocalyptic number.
14466026113347 is a deficient number, since it is larger than the sum of its proper divisors (4822008704453).
14466026113347 is an equidigital number, since it uses as much as digits as its factorization.
14466026113347 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4822008704452.
The product of its (nonzero) digits is 1741824, while the sum is 48.
Adding to 14466026113347 its reverse (74331162066441), we get a palindrome (88797188179788).
The spelling of 14466026113347 in words is "fourteen trillion, four hundred sixty-six billion, twenty-six million, one hundred thirteen thousand, three hundred forty-seven".
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