Base | Representation |
---|---|
bin | 11010111110111111… |
… | …11010111001011101 |
3 | 1101101122001012011210 |
4 | 31133133322321131 |
5 | 214132144330432 |
6 | 10353312535033 |
7 | 1022001235032 |
oct | 153737727135 |
9 | 41348035153 |
10 | 14487105117 |
11 | 6164658551 |
12 | 2983851479 |
13 | 149b4ca864 |
14 | 9b6073389 |
15 | 59bca08cc |
hex | 35f7fae5d |
14487105117 has 4 divisors (see below), whose sum is σ = 19316140160. Its totient is φ = 9658070076.
The previous prime is 14487105109. The next prime is 14487105119. The reversal of 14487105117 is 71150178441.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 14487105117 - 23 = 14487105109 is a prime.
It is a super-3 number, since 3×144871051173 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14487105119) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2414517517 + ... + 2414517522.
It is an arithmetic number, because the mean of its divisors is an integer number (4829035040).
Almost surely, 214487105117 is an apocalyptic number.
It is an amenable number.
14487105117 is a deficient number, since it is larger than the sum of its proper divisors (4829035043).
14487105117 is an equidigital number, since it uses as much as digits as its factorization.
14487105117 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4829035042.
The product of its (nonzero) digits is 31360, while the sum is 39.
The spelling of 14487105117 in words is "fourteen billion, four hundred eighty-seven million, one hundred five thousand, one hundred seventeen".
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