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14493540353 = 47308373199
BaseRepresentation
bin11010111111110000…
…11110000000000001
31101102002011010122212
431133320132000001
5214140321242403
610354102511505
71022110026455
oct153770360001
941362133585
1014493540353
116168253426
122985a35595
13149c9419a6
149b6c6a665
1559c6224d8
hex35fe1e001

14493540353 has 4 divisors (see below), whose sum is σ = 14801913600. Its totient is φ = 14185167108.

The previous prime is 14493540323. The next prime is 14493540371. The reversal of 14493540353 is 35304539441.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14493540353 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14493540353.

It is not an unprimeable number, because it can be changed into a prime (14493540323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 154186553 + ... + 154186646.

It is an arithmetic number, because the mean of its divisors is an integer number (3700478400).

Almost surely, 214493540353 is an apocalyptic number.

It is an amenable number.

14493540353 is a deficient number, since it is larger than the sum of its proper divisors (308373247).

14493540353 is an equidigital number, since it uses as much as digits as its factorization.

14493540353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 308373246.

The product of its (nonzero) digits is 388800, while the sum is 41.

The spelling of 14493540353 in words is "fourteen billion, four hundred ninety-three million, five hundred forty thousand, three hundred fifty-three".

Divisors: 1 47 308373199 14493540353