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14500101335 = 52900020267
BaseRepresentation
bin11011000000100010…
…11111110011010111
31101102112111110122012
431200101133303113
5214144011220320
610354455254435
71022216553626
oct154021376327
941375443565
1014500101335
116170a24825
12298807a41b
1314a10cb125
149b7a976bd
1559cebb4c5
hex36045fcd7

14500101335 has 4 divisors (see below), whose sum is σ = 17400121608. Its totient is φ = 11600081064.

The previous prime is 14500101323. The next prime is 14500101379. The reversal of 14500101335 is 53310100541.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14500101335 - 216 = 14500035799 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14500101335.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1450010129 + ... + 1450010138.

It is an arithmetic number, because the mean of its divisors is an integer number (4350030402).

Almost surely, 214500101335 is an apocalyptic number.

14500101335 is a deficient number, since it is larger than the sum of its proper divisors (2900020273).

14500101335 is an equidigital number, since it uses as much as digits as its factorization.

14500101335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2900020272.

The product of its (nonzero) digits is 900, while the sum is 23.

Adding to 14500101335 its reverse (53310100541), we get a palindrome (67810201876).

The spelling of 14500101335 in words is "fourteen billion, five hundred million, one hundred one thousand, three hundred thirty-five".

Divisors: 1 5 2900020267 14500101335