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14500313441 = 116167124823
BaseRepresentation
bin11011000000100100…
…10011100101100001
31101102112220020120222
431200102103211201
5214144040012231
610354504012425
71022221426205
oct154022234541
941375806528
1014500313441
11617105a119
122988161115
1314a1173833
149b7b10b05
1559d00e27b
hex360493961

14500313441 has 4 divisors (see below), whose sum is σ = 14500554432. Its totient is φ = 14500072452.

The previous prime is 14500313411. The next prime is 14500313447. The reversal of 14500313441 is 14431300541.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 14500313441 - 218 = 14500051297 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14500313441.

It is not an unprimeable number, because it can be changed into a prime (14500313447) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53756 + ... + 178578.

It is an arithmetic number, because the mean of its divisors is an integer number (3625138608).

Almost surely, 214500313441 is an apocalyptic number.

It is an amenable number.

14500313441 is a deficient number, since it is larger than the sum of its proper divisors (240991).

14500313441 is a wasteful number, since it uses less digits than its factorization.

14500313441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 240990.

The product of its (nonzero) digits is 2880, while the sum is 26.

Adding to 14500313441 its reverse (14431300541), we get a palindrome (28931613982).

The spelling of 14500313441 in words is "fourteen billion, five hundred million, three hundred thirteen thousand, four hundred forty-one".

Divisors: 1 116167 124823 14500313441