Base | Representation |
---|---|
bin | 100000111110001011010011… |
… | …100011101101101000111001 |
3 | 201000102211202121200210202211 |
4 | 200332023103203231220321 |
5 | 123001321430202431410 |
6 | 1232224440555255121 |
7 | 42354433544603500 |
oct | 4076132343555071 |
9 | 630384677623684 |
10 | 145010235202105 |
11 | 4222854a3a9619 |
12 | 1431bb5644a4a1 |
13 | 62bb539123170 |
14 | 27b476613d837 |
15 | 11b70b057a68a |
hex | 83e2d38eda39 |
145010235202105 has 48 divisors (see below), whose sum is σ = 220752819141120. Its totient is φ = 90624841227648.
The previous prime is 145010235202099. The next prime is 145010235202153. The reversal of 145010235202105 is 501202532010541.
It is not a de Polignac number, because 145010235202105 - 23 = 145010235202097 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 287907349 + ... + 288410578.
It is an arithmetic number, because the mean of its divisors is an integer number (4599017065440).
Almost surely, 2145010235202105 is an apocalyptic number.
It is an amenable number.
145010235202105 is a deficient number, since it is larger than the sum of its proper divisors (75742583939015).
145010235202105 is a wasteful number, since it uses less digits than its factorization.
145010235202105 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 576318038 (or 576318031 counting only the distinct ones).
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 145010235202105 its reverse (501202532010541), we get a palindrome (646212767212646).
The spelling of 145010235202105 in words is "one hundred forty-five trillion, ten billion, two hundred thirty-five million, two hundred two thousand, one hundred five".
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